AP Physics 1  ·  Unit 1: Kinematics  ·  Lesson 1.2

Deep Dive: Displacement, Velocity & Acceleration

🔬 Deep Dive
This is your textbook for this topic. Take your time. Read it more than once.
1.2.A.1Concept

The Object Model

Before we can describe how something moves, we need to decide how to represent it. Physics uses something called the object model: we pretend the entire object is just a single point in space, with no size or shape.

🔑The object model lets us ignore the complicated stuff — spinning wheels, bending arms, internal vibrations — and focus on one question: where is this thing, and how is that changing?

Think about tracking a car driving across town. Does it matter that the car has four wheels, a back seat, and a trunk? Not for describing its motion from A to B. We just need to know where the car is at each moment. So we shrink it to a point and track that point.

The object still has properties that matter — its mass and charge, for example. We keep those. We just stop worrying about size and shape.

Real objectSize, shape, internal parts — all matter?objectmodelPoint particleOne point. That's it.Position, mass, charge — kept.Size and shape — ignored.
💡When does this break down? When rotation, bending, or internal structure actually matters to the question being asked. A spinning figure skater pulling in their arms is not well-described by the object model alone. But for the AP Physics 1 kinematics unit, the object model is always appropriate.
1.2.A.2Concept

Displacement

When something moves, its position changes. We use the symbol x for position, and we need a reference point — a zero — to measure from. That zero is called the origin.

Displacement is simply the change in position. It answers the question: how far did the object move, and in which direction?

Δx = x − x₀

Here, x is the final position and x₀ is the starting position. The Greek letter delta (Δ) always means "change in" — final minus initial.

-4-3-2-10123456x (m)x₀ = −2 mx = +4 mΔx = +6 mStartEnd
⚠️Displacement is not the same as distance. If you walk 5 meters forward and then 5 meters back, your distance traveled is 10 meters. But your displacement is zero — you ended up exactly where you started. Displacement cares about where you ended up, not how much ground you covered.

Sign matters

Displacement is a vector quantity — it has both size and direction. In one dimension, direction is encoded in the sign: positive means one direction (usually right or up), negative means the other. This is not optional — getting the sign wrong gets the physics wrong.

ExampleWorked Example — Finding Displacement

A dog starts at position x₀ = +3 m, runs to x = −2 m, then back to x = +1 m. What is the dog's displacement? What distance did it travel?

1.2.B.11.2.B.2ConceptMath

Average Velocity

Now that we can describe position changes, we want to describe how fast those changes happen. Average velocity answers: over some period of time, how much displacement happened per second?

v̄ = Δx / Δt

The bar over the v (v̄) means "average." Δt is the time interval — how long the motion took. The result tells you how many meters of displacement occurred per second, on average, during that interval.

🔑Average velocity only uses the starting state and ending state. It doesn't matter what happened in between. A car that drives in circles for an hour and ends up where it started has an average velocity of zero — even though it was moving the whole time.

The position-time graph

On a position vs. time graph, average velocity is the slope of the straight line connecting two points. That's it. Rise over run. Δx over Δt. Steeper slope = faster average velocity.

1680012345time (s)position (m)v̄ = 2.0 m/s

Hover over any point to read its value. The dashed green line shows average velocity — it's the slope from start to end.

ExampleGuided Example — Average Velocity

A student walks from x₀ = 2 m to x = 14 m in 4 seconds, then turns around and walks back to x = 12 m in 1 more second. What is the student's average velocity for the entire 5-second trip?

Step 1Identify what we know
Starting position: x₀ = 2 m  |  Ending position: x = 12 m  |  Total time: Δt = 5 s. Notice we're asked about the entire trip, so we use the start and end only.
1.2.B.3ConceptMath

Average Acceleration

Velocity can change over time. When it does, we say the object is accelerating. Average acceleration measures how quickly velocity changes — it's the velocity version of what velocity is to position.

ā = Δv / Δt

Here, Δv is the change in velocity (v − v₀) and Δt is the time interval. The units are meters per second per second, written m/s². That means: for every second that passes, velocity changes by this many m/s.

On a velocity vs. time graph, average acceleration is the slope of the line connecting two velocity values. Same idea as before — just applied to velocity instead of position.

0246810012345time (s)velocity (m/s)ā = -0.2 m/s²

Hover any point to read velocity. The dashed amber line is average acceleration — slope from first to last velocity.

ExampleWorked Example — Average Acceleration

A car is traveling at v₀ = +20 m/s. It brakes and slows to v = +8 m/s over 4 seconds. What is the car's average acceleration?

1.2.B.4Concept⚠ Watch Out

What Acceleration Actually Means

This is where most students — and many teachers — get tripped up. Read this section slowly.

🔑An object is accelerating any time its velocity changes — whether that means speeding up, slowing down, or changing direction. All three are acceleration.

Speed vs. velocity — the critical difference

Speed is how fast something is moving — just a number, always positive. Velocity is speed with direction — it can be positive or negative. Acceleration responds to changes in velocity, not just speed.

Three scenarios, all acceleration

Speeding up

A car goes from 0 m/s to 30 m/s heading east. Velocity changed in magnitude. This is acceleration.

v₀ = +5 m/svf = +20 m/s· Δv is positive → positive acceleration
Slowing down

That same car hits the brakes. It's still moving east, but slowing. Velocity is still positive but decreasing. This is also acceleration — a negative one.

v₀ = +20 m/svf = +5 m/s· Δv is negative → negative acceleration
Changing direction

A ball rolls north at 4 m/s, bounces off a wall, and rolls south at 4 m/s. Speed didn't change at all. But velocity went from +4 to −4. That's a massive change in velocity — huge acceleration during the bounce.

v₀ = +4 m/svf = −4 m/s· Δv = −8 m/s → large acceleration even though speed is unchanged
⚠️Common misconception: "Deceleration means negative acceleration." Not always. If an object is moving in the negative direction and slowing down, its acceleration is actually positive — because velocity is becoming less negative (increasing). Always think about the direction of the velocity change, not just whether the object is slowing down.
ExampleGuided Example — Negative Acceleration, Positive Direction

A ball rolls left at −6 m/s and hits a rough patch, slowing to −2 m/s over 2 seconds. Is the acceleration positive or negative?

Step 1Set up what we know
v₀ = −6 m/s (moving left)  ·  v = −2 m/s (still moving left, but slower)  ·  Δt = 2 s
1.2.B.5Concept

Instantaneous Values

Average velocity tells us what happened over an interval. But what if we want to know the velocity at one exact moment? That's instantaneous velocity.

Here's the key idea: if you make the time interval smaller and smaller, the average velocity gets closer and closer to the instantaneous velocity at that moment. In the limit — as Δt approaches zero — average velocity becomes instantaneous velocity.

💡You don't need calculus to understand this idea — you just need to see it happening. Use the tool below to shrink the time interval and watch the average velocity converge on the true instantaneous value.

Using the position function x = t², watch what happens to average velocity as the time interval shrinks around t = 2 s:

Δt = 0.1 s
x(t₀) = (2)² = 4 m
x(t₀ + Δt) = (2.1)² = 4.410 m
v̄ = Δx / Δt = 4.100 m/s≈ 4.0 m/s (instantaneous!)

The true instantaneous velocity at t = 2 s is exactly 4.0 m/s. As Δt shrinks, the average gets closer and closer.

The same logic applies to acceleration: average acceleration calculated over a very small time interval gives a value very close to the instantaneous acceleration at that moment.

🔑On a position-time graph, the instantaneous velocity at any point is the slope of the tangent line at that point — the slope of the curve itself, not a chord connecting two points. On a velocity-time graph, instantaneous acceleration is the slope of the tangent to that curve.
ExampleWorked Example — Estimating Instantaneous Velocity

A runner's position is described by x = t² (in meters, with t in seconds). Estimate the instantaneous velocity at t = 3 s by using a very small time interval.

← Back to Lesson 1.2Ready for the practice set? Head back and check off your self-check items first.
Built with v0